einfaches timen vom brute-force
This commit is contained in:
@@ -15,16 +15,8 @@ class BruteForceSolver:
|
||||
self.game.set_direction(x, y, Direction.UP)
|
||||
|
||||
def solve(self) -> Generator[None]:
|
||||
attempts = 0
|
||||
required = 4 ** (self.game.width * self.game.height)
|
||||
while not self.game.solved():
|
||||
yield
|
||||
attempts += 1
|
||||
|
||||
print(
|
||||
f"{attempts:0>{len(str(required))}}/{required} ({attempts / required * 100}%) ",
|
||||
end="\r",
|
||||
)
|
||||
self.game.turn_cw(0, 0)
|
||||
for prev, curr in pairwise(
|
||||
chain(
|
||||
|
||||
24
src/algorithms/profile.py
Normal file
24
src/algorithms/profile.py
Normal file
@@ -0,0 +1,24 @@
|
||||
import time
|
||||
from multiprocessing import Pool
|
||||
|
||||
from src.algorithms.bruteforce import BruteForceSolver
|
||||
from src.net import NetGame
|
||||
|
||||
|
||||
def test_run() -> float:
|
||||
game = NetGame(3, 3)
|
||||
solver = BruteForceSolver(game)
|
||||
a = time.perf_counter()
|
||||
for _ in solver.solve():
|
||||
pass
|
||||
b = time.perf_counter()
|
||||
return b - a
|
||||
|
||||
|
||||
if __name__ == "__main__":
|
||||
total = 0
|
||||
with Pool() as p:
|
||||
processes = [p.apply_async(test_run) for _ in range(100)]
|
||||
for proc in processes:
|
||||
total += proc.get()
|
||||
print(total)
|
||||
Reference in New Issue
Block a user